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**QuasiChameleon**: @Manas SrivastavaAccording to Kristian, the number of distinct possibilities is floor((d(n^2) + 1) / 2), which for 6 becomes floor([(2*a2 + 1)*(2*...**Jean-Marie Hachey**: Table 1 Application and non-application of the 6/9 reversal and its effects on the number of distinct valid combinations generated.http://img11....**Sanchit Handa**: Awesome explanation.Both path compression & union by rank cannot be applied together. Right?...**Ben**: coins "c" in square brackets...**Ben**: Sorry I'm not sure what happened but coins1 is supposed to be coins[c][/c]...**Ben**: I used a recursive algorithm, but I am not sure how it would compare to the other solutions.[code language="java"] class Main { public static...

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